-63x^2-103x-42=0

Solution for -63x^2-103x-42=0 equation:

-63x^2-103x-42=0

a = -63; b = -103; c = -42;
Δ = b2-4ac
Δ = -1032-4·(-63)·(-42)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-103)-5}{2*-63}=\frac{98}{-126}
=-7/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-103)+5}{2*-63}=\frac{108}{-126}
=-6/7
$